| Dec. 22nd, 2006 @ 04:07 pm I see your Nash Equilibrium and raise you... |
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Current Mood:  accomplished
To prove I'm not just a pretty face, I've solved one of the greatest problems plaguing mankind.
Man has asked the age-old question of "Dude, I've got these two chicks that I like but don't know which one to choose... What do I do?" Some may flip a coin. Some may throw their arms up into the air, declare it all too much and become a monk. Not any more!
My solution involves game theory. Yeah, yeah, you say. I've heard it before. Not this one! What you do is get both girls to play a game of Prisoner's Dilemma where they have two choices: go with you (Hot), or not (Not). Let's look at the payoff table:
| Hot | Not |
| Hot | Polygamy! Woo! | You got a girlfriend! |
| Not | You got a girlfriend! | You're single! |
This is a zero-sum game for the girls, but a win-win situation for you. In half the cases you end up with a girlfriend. In one-quarter of the cases you are allowed to go back to the love game, or indeed, play this Prisoner's Dilemma game again! There's a nonzero chance of getting what you want so play until you get it. The last payoff is great: either threesomes or at least a tag-team approach to love.
But you might say, "Nuh-uh, girls won't fall for threesomes!" This is the genius of the plan: the decision is entirely in their hands. They will have to take the blame for the polygamy and so you constantly have the upper hand.
The further beauty to this solution is that it generalizes to n girls. The chance of polygamy is polynomial in n, and the chance of singledom approaches zero as n is large.
I know this plan is too brilliant to keep as theory, which is why you should put it to use today, on Global Orgasm Day. Get out there and do your local game theorist proud! And remember me next time they call for nominations for the Nobel Prize in Booty-ology. |
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